12x^2-43x=-35

Solution for 12x^2-43x=-35 equation:

12x^2-43x=-35

We move all terms to the left:

12x^2-43x-(-35)=0

We add all the numbers together, and all the variables

12x^2-43x+35=0

a = 12; b = -43; c = +35;
Δ = b2-4ac
Δ = -432-4·12·35
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-13}{2*12}=\frac{30}{24}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+13}{2*12}=\frac{56}{24}
=2+1/3
$